2704t=-16t^2+2704

Solution for 2704t=-16t^2+2704 equation:

2704t=-16t^2+2704

We move all terms to the left:

2704t-(-16t^2+2704)=0

We get rid of parentheses

16t^2+2704t-2704=0

a = 16; b = 2704; c = -2704;
Δ = b2-4ac
Δ = 27042-4·16·(-2704)
Δ = 7484672
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7484672}=\sqrt{43264*173}=\sqrt{43264}*\sqrt{173}=208\sqrt{173}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2704)-208\sqrt{173}}{2*16}=\frac{-2704-208\sqrt{173}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2704)+208\sqrt{173}}{2*16}=\frac{-2704+208\sqrt{173}}{32}
$